4x^2-4x-168/2x+12=-20

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Solution for 4x^2-4x-168/2x+12=-20 equation: 


x in (-oo:+oo)

4*x^2-(4*x)-((168/2)*x)+12 = -20 // + 20

4*x^2-(4*x)-((168/2)*x)+12+20 = 0

4*x^2-4*x-84*x+12+20 = 0

4*x^2-88*x+32 = 0

DELTA = (-88)^2-(4*4*32)

DELTA = 7232

DELTA > 0

x = (7232^(1/2)+88)/(2*4) or x = (88-7232^(1/2))/(2*4)

x = (8*113^(1/2)+88)/8 or x = (88-8*113^(1/2))/8

x in { (88-8*113^(1/2))/8, (8*113^(1/2)+88)/8 }

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